
curbstop
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Amounts *DELETED*
#649569  12/05/12 11:54 AM (4 years, 5 months ago) 


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phychotron
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Re: Amounts [Re: curbstop]
#649576  12/05/12 01:14 PM (4 years, 5 months ago) 


concentration*amount + concentration*amount = concentration*amount .8x + 0.0*4L = .2(x+4L), solve for x
.8x= .2x+.16 x =.2666 L 266ml per 4L
*messed up, see real answers below
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Edited by phychotron (12/10/12 08:46 PM)

curbstop
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Re: Amounts *DELETED* [Re: phychotron]
#649581  12/05/12 02:17 PM (4 years, 5 months ago) 


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phychotron
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Re: Amounts [Re: curbstop]
#649597  12/05/12 03:59 PM (4 years, 5 months ago) 


solution 1 + solution 2 = solution 1+2. Just put in the known variables, and solve for the unknown.
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juke adro
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Re: Amounts [Re: curbstop]
#650173  12/08/12 11:11 PM (4 years, 5 months ago) 


Lets pretend 100mls water = 100% now you want a 2% solution You have you 100% solution which is 100mls Now you just remove 2mls water and add 2mls of whatever you want And it will now be 2% and so on and on If you want 20% take out 20mls and add 20mls of whatever, so your solution will now be 100% solution but have 20% whatever. That can work for anything like powders or whatever you like You can also add this ontop of your 100mls 100% so you will end up having 120mls or whatever

I eat animals and most things that live in the sea, I'm not green but I smoke it and I litter to keep cunts like you in a job so fuck off.

curbstop
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Re: Amounts *DELETED* [Re: juke adro]
#650227  12/09/12 11:35 AM (4 years, 5 months ago) 


Post deleted by curbstopReason for deletion: Sdr

juke adro
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Re: Amounts [Re: curbstop] 1
#650245  12/09/12 03:00 PM (4 years, 5 months ago) 


It is that easy! Your just not getting it and dont understand simple math. So im leaving it as that.

I eat animals and most things that live in the sea, I'm not green but I smoke it and I litter to keep cunts like you in a job so fuck off.

curbstop
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Re: Amounts *DELETED* [Re: juke adro]
#650281  12/09/12 07:09 PM (4 years, 5 months ago) 


Post deleted by curbstopReason for deletion: Sdr

juke adro
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Re: Amounts [Re: curbstop]
#650295  12/09/12 08:39 PM (4 years, 5 months ago) 


80% is 100% put 1.6mls ha in your solution and its 2%

I eat animals and most things that live in the sea, I'm not green but I smoke it and I litter to keep cunts like you in a job so fuck off.

Hawksresurrection
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To make it exact, subtract 1.6mls out of solution a.
 Dude she isn't as young as she use to be.
niteowl

curbstop
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Hawksresurrection
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Re: Amounts [Re: curbstop]
#650467  12/10/12 05:52 PM (4 years, 5 months ago) 


Yeah, sorry was pretty stoned last night. If it was a liquid it would be taking out about 2.5 mls and adding 2.5 mls of the solution to bring it to 2%
I'm trying to figure this powder thing out now.
 Dude she isn't as young as she use to be.
niteowl

Hawksresurrection
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And this is per liter, not gallon that I'm doing all this in. Makes life a lot easier.
 Dude she isn't as young as she use to be.
niteowl

Hawksresurrection
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So take 1000mls water, add 1250mls of your humic acid solution, this will give you a 100mg/ml solution. We'll call this solution A
Take you 1000mls of water, take 250 of that out, then add 250mls of solution A. This will achieve a roughly 20% solution.
 Dude she isn't as young as she use to be.
niteowl

phychotron
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yo guys, I actually used a math book, just do a little bit of algebra and it will be done for you. I also wrote down the wrong numbers because I was looking at the wrong part of the paper. I multiplied .2*4=0.16
"So take 1000mls water, add 1250mls of your humic acid solution"
your looking at a 44.4% solution that way. yours is more like if you had 4L.
Here I use 1 gallon = 3.76L
Solution = Concentration * Amount Where Concentration is a %, between 0 and 1. 80% = .80 Amount = Volume of liquid
Solution 1 + Solution 2 = Solution 3
Solution 1 = 0.80 * X (Amount unknown) Solution 2 = 0.00 * 3.76L Amount (Water) = 0 Solution 3 = (Desired Concentration) * Amount(1+2)
Solution 1 + Solution 2 = Solution 3 0.80*X + 0.0*3.76 = 0.20 * (X + 3.76)L Simplify (remove 0's, distribute 0.20 on right) 0.80x = 0.20x + 0.752L
put all the unknowns on one side, everything else on the other... subtract 0.20x from both sides 0.60x = 0.752L
Solve for x by dividing both sides by 0.60
X = 1.253L per 3.76L (1 gallon)
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Hawksresurrection
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So if you know what your doing, tell him his answer then. Cause what I put down makes sense to me.
 Dude she isn't as young as she use to be.
niteowl

phychotron
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Probably a more important calculation is: Make 1 gallon of 20% HA solution from an 80% Solution. Like if you had a gallon jug and just wanted to top it off, not make 5.25L of it.
Same thing, just need to substitute another variable and solve it in terms of the other.
X = Amount HA solution, Y = Amount Water. ( in liters) 1Gal = 3.76L
0.80*X + 0.00*Y = 0.20(X+Y) and we know that X + Y = 3.76L Solve in terms of Y (subtract X from both sides) Y = 3.76  X Substitute in 3.76  X for Y, Which brings the equation to 0.80*X + 0.00*(3.76  X) = 0.20(X + 3.76  X) 0.80X = 0.20(3.76) 0.80X = .752 Divide both sides by 0.80 and X = .940 Liters, or 940mL of HA Solution to make 1 Gallon @ 20%
*hawk, your logic has him mix two times. If I'm cutting a 10" board to 6", I don't cut it at 8" first, then again at 6
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Hawksresurrection
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Mine did get the right solution thought right? I just wanna make sure that my logic is correct.
 Dude she isn't as young as she use to be.
niteowl

phychotron
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I just went through the first mixingit makes 44%, What is the final volume of 20% solution?
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phychotron
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Solution A: 0.80(1250mL) + 0.00*(1000mL) = X*(2250mL) X = 0.44444
Solution A = 44% HA
so if C= the final concentration,
0.44(250mL) + 0.00(750mL) = C(1000mL) concentration = 11%.
you somehow magically come up with mg's in your equation " a 100mg/ml solution", but mass is never considered
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Edited by phychotron (12/10/12 08:27 PM)

